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Community Project (1)

Resource type Integration: Laplace Transforms SOURCE
A zip file containing LaTeX source and eps files for the quick reference leaflet 'Integration: Laplace Transforms' contributed to the mathcentre Community Project by Leslie Fletcher, Liverpool John Moores University

Practice & Revision (2)

Resource type Calculus Refresher
A refresher booklet on Calculus
Resource type Cwrs Gloywi Calcwlws
A Calculus Refresher. This booklet revises techniques in calculus (differentiation and integration). This is a welsh language version

Quick Reference (2)

Resource type Integration as summation
An integral is defined as an infinite sum. This leaflet explains how this is done. This notion is important when we want to apply integration in many fields.
Resource type Integration: Laplace Transforms
Reviews the techniques of integration needed to find and manipulate Laplace Transforms. This Quick Reference leaflet is contributed to the mathcentre Community Project by Leslie Fletcher and reviewed by Martin Randles, Liverpool John Moores University.

Staff Resources (1)

Resource type Maths EG Teacher Interface
The teacher interface for Maths EG which may be used for computer-aided assessment of maths, stats and numeracy from GCSE to undergraduate level 2. These resources have been made available under a Creative Common licence by Martin Greenhow and Abdulrahman Kamavi, Brunel University. Teachers need to login to the system, after which they may use it to compose their own tests by selecting (specifically or randomly) questions from the entire database of questions. Instructions are available from the title page.

Teach Yourself (17)

Resource type Finding areas by integration
This unit looks at how to calculate the area bounded by a curve using integration.
Resource type Integrating Algebraic Fractions (with STACK)
Sometimes the integral of an algebraic fraction can be found by first expressing the algebraic fraction as the sum of its partial fractions. In this unit we will illustrate this idea. We will see that it is also necessary to draw upon a wide variety of other techniques such as completing the square, integration by substitution, using standard forms, and so on. Additionally, this file has links to STACK on-line exercises Note there is a mathtutor video to accompany this text.
Resource type Integration as a summation
The second major component of the Calculus is called integration. This may be introduced as a means of finding areas using summation and limits. We shall adopt this approach in the present Unit. In later units, we shall also see how integration may be related to differentiation.
Resource type Integration as the reverse of differentiation
This unit explain integration as the reverse of differentiation.
Resource type Integration by parts
A special rule, integration by parts, is available for integrating products of two functions. This unit derives and illustrates this rule with a number of examples.
Resource type Integration by parts (with STACK)
A special rule, integration by parts, is available for integrating products of two functions. This unit derives and illustrates this rule with a number of examples. This file has links to STACK on-line exercises. Note there is an accompanying mathtutor video.
Resource type Integration by substitution
This unit explain integration by substitution.
Resource type Integration by substitution (with STACK)
There are occasions when it is possible to perform an apparently difficult piece of integration by first making a substitution. This has the effect of changing the variable and the integrand. When dealing with definite integrals, the limits of integration can also change. In this unit we will meet several examples of integrals where it is appropriate to make a substitution. This is text to accompany a mathtutor video, and there are links to on-line exercises provided through the STACK system
Resource type Integration that leads to logarithms
The derivative of ln x is 1/x. As a consequence, if we reverse the process, the integral of 1/x is ln x+c. In this unit we generalise this result and see how a wide variety of integrals result in logarithm functions.
Resource type Integration that leads to logarithms (with STACK)
The derivative of ln x is 1/x. As a consequence, if we reverse the process, the integral of 1/x is ln x+c. In this unit we generalise this result and see how a wide variety of integrals result in logarithm functions. This file has links to STACK on-line exercises. Note there is a mathtutor video to accompany this text.
Resource type Integration using a table of anti-derivatives
We may regard integration as the reverse of differentiation. So if we have a table of derivatives, we can read it backwards as a table of anti-derivatives. When we do this, we often need to deal with constants which arise in the process of differentiation.
Resource type Integration using a table of anti-derivatives (with STACK)
We may regard integration as the reverse of differentiation. So if we have a table of derivatives, we can read it backwards as a table of anti-derivatives. When we do this, we often need to deal with constants which arise in the process of differentiation. This file has links to STACK on-line exercises. Note there is a mathtutor video tutorial to accompany this text.
Resource type Integration using partial fractions 1
Sometimes the integral of an algebraic fraction can be found by first expressing the algebraic fraction as the sum of its partial fractions. In this unit we will illustrate this idea. We will see that it is also necessary to draw upon a wide variety of other techniques such as completing the square, integration by substitution, using standard forms, and so on.
Resource type Integration using partial fractions 2
In this unit we are going to look at how we can integrate some more algebraic fractions. We shall concentrate on the case where the denominator of the fraction involves an irreducible quadratic factor. The case where all the factors of the denominator are linear has been covered in the first unit on integration using partial fractions.
Resource type Integration using trig identities and trig substitutions (with STACK)
This unit explains how trig identities and trig substitutions can help when finding integrals. This file has links to STACK on-line exercises. Note there is an accompanying mathtutor video.
Resource type Integration using trig identities and trig substitutions.
This unit explains how trig identities and trig substitutions can help when finding integrals.
Resource type Volumes of solids of revolution
We sometimes need to calculate the volume of a solid which can be obtained by rotating a curve about the x-axis. There is a straightforward technique which enables this to be done, using integration. This unit will explain how.

Test Yourself (21)

Resource type Diagnostic Test - Integration - Finding volumes
This resource is released under a Creative Commons license Attribution-Non-Commercial-No Derivative Works and the copyright is held by Skillbank Solutions Ltd.
Resource type Diagnostic Test - Integrating Algebraic Fractions 1
This resource is released under a Creative Commons license Attribution-Non-Commercial-No Derivative Works and the copyright is held by Skillbank Solutions Ltd.
Resource type Diagnostic Test - Integrating Algebraic Fractions 2
This resource is released under a Creative Commons license Attribution-Non-Commercial-No Derivative Works and the copyright is held by Skillbank Solutions Ltd.
Resource type Diagnostic Test - Integration - Finding areas
This resource is released under a Creative Commons license Attribution-Non-Commercial-No Derivative Works and the copyright is held by Skillbank Solutions Ltd.
Resource type Diagnostic Test - Integration as a summation
This resource is released under a Creative Commons license Attribution-Non-Commercial-No Derivative Works and the copyright is held by Skillbank Solutions Ltd.
Resource type Diagnostic Test - Integration as the reverse of Differentiation
This resource is released under a Creative Commons license Attribution-Non-Commercial-No Derivative Works and the copyright is held by Skillbank Solutions Ltd.
Resource type Diagnostic Test - Integration by parts
This resource is released under a Creative Commons license Attribution-Non-Commercial-No Derivative Works and the copyright is held by Skillbank Solutions Ltd.
Resource type Diagnostic Test - Integration requiring use of trigonometric identities
This resource is released under a Creative Commons license Attribution-Non-Commercial-No Derivative Works and the copyright is held by Skillbank Solutions Ltd.
Resource type Diagnostic Test - Integration that leads to log functions
This resource is released under a Creative Commons license Attribution-Non-Commercial-No Derivative Works and the copyright is held by Skillbank Solutions Ltd.
Resource type Diagnostic Test - Integration using a table and standard rules
This resource is released under a Creative Commons license Attribution-Non-Commercial-No Derivative Works and the copyright is held by Skillbank Solutions Ltd.
Resource type Diagnostic Text - Integration by substitution
This resource is released under a Creative Commons license Attribution-Non-Commercial-No Derivative Works and the copyright is held by Skillbank Solutions Ltd.
Resource type Exercise - Integrating algebraic fractions 1
This resource is released under a Creative Commons license Attribution-Non-Commercial-No Derivative Works and the copyright is held by Skillbank Solutions Ltd.
Resource type Exercise - Integrating algebraic fractions 2
This resource is released under a Creative Commons license Attribution-Non-Commercial-No Derivative Works and the copyright is held by Skillbank Solutions Ltd.
Resource type Exercise - Integration - Finding areas
This resource is released under a Creative Commons license Attribution-Non-Commercial-No Derivative Works and the copyright is held by Skillbank Solutions Ltd.
Resource type Exercise - Integration as the reverse of Differentitation
This resource is released under a Creative Commons license Attribution-Non-Commercial-No Derivative Works and the copyright is held by Skillbank Solutions Ltd.
Resource type Exercise - Integration by parts
This resource is released under a Creative Commons license Attribution-Non-Commercial-No Derivative Works and the copyright is held by Skillbank Solutions Ltd.
Resource type Exercise - Integration by substitution
This resource is released under a Creative Commons license Attribution-Non-Commercial-No Derivative Works and the copyright is held by Skillbank Solutions Ltd.
Resource type Exercise - Integration requiring use of trigonometric identities
This resource is released under a Creative Commons license Attribution-Non-Commercial-No Derivative Works and the copyright is held by Skillbank Solutions Ltd.
Resource type Exercise - Integration that leads to log functions
This resource is released under a Creative Commons license Attribution-Non-Commercial-No Derivative Works and the copyright is held by Skillbank Solutions Ltd.
Resource type Exercise - Integration to find volumes
This resource is released under a Creative Commons license Attribution-Non-Commercial-No Derivative Works and the copyright is held by Skillbank Solutions Ltd.
Resource type Exercise - Integration using a table and standard rules
This resource is released under a Creative Commons license Attribution-Non-Commercial-No Derivative Works and the copyright is held by Skillbank Solutions Ltd.

Video (11)

Resource type Finding areas by integration
Integration can be used to calculate areas. In simple cases, the area is given by a single definite integral. But sometimes the integral gives a negative answer which is minus the area, and in more complicated cases the correct answer can be obtained only by splitting the area into several parts and adding or subtracting the appropriate integrals. (Mathtutor Video Tutorial) This resource is released under a Creative Commons license Attribution-Non-Commercial-No Derivative Works and the copyright is held by Skillbank Solutions Ltd.
Resource type Integrating algebraic fractions (1)
Sometimes the integral of an algebraic fraction can be found by first expressing the algebraic fraction as the sum of its partial fractions. In this unit we will illustrate this idea. We will see that it is also necessary to draw upon a wide variety of other techniques such as completing the square, integration by substitution, using standard forms, and so on. (Mathtutor Video Tutorial) This resource is released under a Creative Commons license Attribution-Non-Commercial-No Derivative Works and the copyright is held by Skillbank Solutions Ltd.
Resource type Integrating algebraic fractions (2)
Sometimes the integral of an algebraic fraction can be found by first expressing the algebraic fraction as the sum of its partial fractions. In this unit we look at the case where the denominator of the fraction involves an irreducible quadratic expression. (Mathtutor Video Tutorial) This resource is released under a Creative Commons license Attribution-Non-Commercial-No Derivative Works and the copyright is held by Skillbank Solutions Ltd.
Resource type Integration as a summation
The second major component of the Calculus is called integration. This may be introduced as a means of finding areas using summation and limits. We shall adopt this approach in the present Unit. In later units, we shall also see how integration may be related to differentiation. (Mathtutor Video Tutorial) This resource is released under a Creative Commons license Attribution-Non-Commercial-No Derivative Works and the copyright is held by Skillbank Solutions Ltd.
Resource type Integration as the reverse of differentiation
This unit explain integration as the reverse of differentiation. (Mathtutor Video Tutorial) This resource is released under a Creative Commons license Attribution-Non-Commercial-No Derivative Works and the copyright is held by Skillbank Solutions Ltd.
Resource type Integration by parts
A special rule, integration by parts, is available for integrating products of two functions. This unit derives and illustrates this rule with a number of examples. (Mathtutor Video Tutorial) This resource is released under a Creative Commons license Attribution-Non-Commercial-No Derivative Works and the copyright is held by Skillbank Solutions Ltd.
Resource type Integration by substitution
There are occasions when it is possible to perform an apparently difficult piece of integration by first making a substitution. This has the effect of changing the variable and the integrand. When dealing with definite integrals, the limits of integration can also change. In this unit we will meet several examples of integrals where it is appropriate to make a substitution. (Mathtutor Video Tutorial) This resource is released under a Creative Commons license Attribution-Non-Commercial-No Derivative Works and the copyright is held by Skillbank Solutions Ltd.
Resource type Integration that leads to log functions
This unit is concerned with integrals which lead to logarithms. Whenever the integrand is fraction with denominator f(x) and numerator f'(x) the result of integrating is the natural logarithm of f(x). This unit illustrates this behaviour with several examples. (Mathtutor Video Tutorial) This resource is released under a Creative Commons license Attribution-Non-Commercial-No Derivative Works and the copyright is held by Skillbank Solutions Ltd.
Resource type Integration using a table of anti-derivatives
We may regard integration as the reverse of differentiation. So if we have a table of derivatives, we can read it backwards as a table of anti-derivatives. When we do this, we often need to deal with constants which arise in the process of Differentiation. (Mathtutor Video Tutorial) This resource is released under a Creative Commons license Attribution-Non-Commercial-No Derivative Works and the copyright is held by Skillbank Solutions Ltd.
Resource type Integration using trid identities or a trig substitution
This unit explains how trig identities and trig substitutions can help when finding integrals. (Mathtutor Video Tutorial) This resource is released under a Creative Commons license Attribution-Non-Commercial-No Derivative Works and the copyright is held by Skillbank Solutions Ltd.
Resource type Volumes of solids of revolution
We sometimes need to calculate the volume of a solid which can be obtained by rotating a curve about the x-axis. There is a straightforward technique which enables this to be done, using integration. (Mathtutor Video Tutorial) This resource is released under a Creative Commons license Attribution-Non-Commercial-No Derivative Works and the copyright is held by Skillbank Solutions Ltd.

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